chem howmuchhowfasthowfar

Reactivity 2.3.6 - the equilibrium law is the basis for quantifying the composition of an equilibrium mixture
calculating the equilibrium constant from equilibrium concentrations

just plug the values into the equilibrium constant expression

calculating the equilibrium constant from initial concentrations

steps:

  1. write the balanced equation
  2. under the equation, write in the values of the concentrations of each component using 3 rows: initial, change and equilibrium
    • initial represents the concentration originally placed in the flask. unless stated otherwise, the initial product concentration is 0
    • change represents the amount that reacts to each equilibrium. a minus sign for reactants represents a decrease in concentration as they are used up, and a plus sign for products represents an increase in concentration as they form. the changes that occur must be in the same ratio as the coefficients in the balanced equation, so if we know one of the change values, we can deduce the others
    • equilibrium represents the concentration present in the equilibrium mixture. this can be calculated by applying the amount of change to the initial concentration for each component
  3. write the expression for from the balanced equation. substitute the values for equilibrium concentration and calculate

for more complex situations when calculating equilibrium concentrations given and initial concentrations, let the change be and solve from there

calculations when the equilibrium constant is very small
  • when , the reaction lies far to the left and the equilibrium mixture contains mainly reactants
  • the change from the initial amount of reactant to the equilibrium amount is close to zero
  • therefore the following approximation can also be made:
interesting

the oxidation of to form occurs during the formation of smog. when of was reacted with of in a container at 500C, the equilibrium mixture was found to contain of . calculate the equilibrium constant for the reaction at this temperature

solution

$$
K=\ce{\frac{[NO_{2}]^{2}}{[NO]^{2}[O_{2}]}=\frac{0.10^{2}}{0.20^{2}\times 0.25}=1.0}