IR radiation produces bond
total degrees of freedom is
bond energy is proportional to wavenumber
reduced mass: smaller reduced mass easier to vibrate
think of bond as spring, reduced mass acts as weight on end of spring
comparing wavenumber of carbonyl compounds:
CC(=O)Clhighest (no resonance and inductive effect draws electron density away from carbon even more, strengthening double bond in carbonyl)
CC(=O)Cstandard to compare to
CC(=O)C=Cslightly weaker due to resonance from C=C to carbonyl oxygen, giving carbonyl group single bond character
CC(=O)Nstrongest resonance from nitrogen due to freely available lone pairs
ring strain and wavenumber
C1C(=O)CCCC1highest wavenumber because properly sp2 satisfied
O=C1CCCC1next, less satisfied with sp2
O=C1CCC1next
O=C1CC1lowest, least satisfied with sp2
as we increase ring strain, we increase s character in the carbonyl, increasing p availability for side on side overlap, thus shortening/strengthening carbonyl
degrees of freedom
rotation has 2 or 3
- linear molecule has 2 because rotation along bond axis does “nothing”
- otherwise 3
translation has 3
- move in x, y, z
vibration has whatever is left
- linear
- non-linear
stretching a bond requires more energy than bending
- stretching bond needs to overcome strong covalent electrostatic attraction
- bending bond needs not this
in terms of energy/wavenumber
asymmetric stretch > symmetric stretch > in plane bending > out of plane bending
asymmetric stretch needs more energy than symmetric stretch because
- electron cloud distorts very severely (add on one side, remove on another, requires much to equilibrate)
- requires central atom to vibrate to stabilise centre of mass